Question

a) Percy's goal is to create 22g of oxygen gas in one hour. How many moles of oxygen gas does it need to produce? Round to the nearest tenth (1 decimal place). b) Based on the molar ratios found in Step 2 (which is 2:1 ratio), how many moles of carbon dioxide must be reacted to create the oxygen required. Round to the nearest tenth.

Answer 1

Step-by-step explanation:

a) We have to find the number of moles of oxygen gas that are present in 22 g of it. To convert from grams to moles we usually use the molar mass. To find the molar mass of oxygen gas we need the atomic mass of O.

atomic mass of O = 16.00 amu

molar mass of O = 16.00 g/mol

molar mass of O₂ = 2 * 16.00 g/mol

molar mass of O₂ = 32.00 g/mol

moles of O₂ = 22 g * 1 mol/(32.00 g)

moles of O₂ = 0.6875 moles = 0.7 moles

b) 2 CO₂ --> 2 CO + O₂

According to the coefficients of the reaction 2 moles of CO₂ will produce 2 moles of CO and 1 mol of O₂. Then the molar ratio between CO₂ and O₂ is 2:1. We will use that ratio to find the number of moles of CO₂ that are required to produce 0.7 moles of O₂.

2 moles of CO₂ : 1 mol of O₂

moles of CO₂ = 0.7 moles of O₂ * 2 moles of CO₂/(1 mol of O₂)

moles of CO₂ = 1.4 moles

Answer:

a) Percy has to produce 0.7 moles of oxygen gas.

b) 1.4 moles of carbon dioxide are required.