Question

What is the initial volume of a gas that starts at 120 K and expands to anew volume of 45 L at 300 K?

Answer 1

Answer: Initial volume = 18 L

Calculations:

We are given -

• Volume 1 (V1) = ?

,

• Temperature (T1) = 120K

,

• Volume 2(V2) = 45L

,

• Temperature (T2) = 300K

We can use Charles law equation to solve for initial volume :

`(V_1)/(T_1)=(V_2)/(T_2)`

Replacing the given parameters into Charles law equation, we get that V1 is :

`\begin{gathered} V_1=(V_2)/(T_2)\cdot T_1 \\ \text{ =}\frac{45L}{300K\text{ }}\cdot120K\text{ } \\ \text{ = 18L} \end{gathered}`

This means that the initial volume = 18 L