Question

One of the player pass the other at t = 1.8s, solve part c

Answer 1

x = -0.46 m

Step-by-step explanation:

First, we need to calculate the time when one of the players pass the other, so need to solve the following equation:

`\begin{gathered} x_1=x_2 \\ -8.2+4.3t=-7.3+3.8t \end{gathered}`

So, we get:

`\begin{gathered} 4.3t-3.8t=-7.3+8.2 \\ 0.5t=0.9 \\ t=(0.9)/(0.5)=1.8\text{ s} \end{gathered}`

Now, to know the location, we need to replace t by 1.8s on either of the equations for x1 or x2, so replacing in x1, we get:

`\begin{gathered} x_1=-8.2+4.3t \\ x_1=-8.2+4.3(1.8) \\ x_1=-8.2+7.74 \\ x_1=-0.46\text{ m} \end{gathered}`

Therefore, the location is:

x = -0.46 m