Question

The weights of the babies born in Martin County Hospital are normally distributed with a mean of 119 ounces and astandard deviation of 20 ounces. What percent of the babies have a birth weight between 59 and 179 ounces?

Answer 1

First, let's calculate the z-score corresponding to x = 59 and x = 179, using the formula below:

`\begin{gathered} z_1=(59-119)/(20)=(-60)/(20)=-3\\ \\ z_2=(179-119)/(20)=(60)/(20)=3 \end{gathered}`

Now, let's look at the z-table for the probability corresponding to each value of z.

for z = -3, we have a probability of 0.0013.

For z = 3, we have a probability of 0.9987.

Calculating the interval between these values, we have:

`P=0.9987-0.0013=0.9974=99.74\%`