Given the line passes through the point (0,3 ) and (2, 3)
then
![m=(y2-y1)/(x2-x1)](https://img.qammunity.org/2023/formulas/mathematics/high-school/wt3vklmulg2853jxzclws9uvfaplhmpgv7.png)
![m=(3-3)/(2-0)](https://img.qammunity.org/2023/formulas/mathematics/college/zw59yyg1sudcr0qjykagoefz7cvtwjxuuc.png)
![m=(0)/(2)=0](https://img.qammunity.org/2023/formulas/mathematics/college/r0qrnd798i4rqpqm7oi9tx6sxh6pff97xy.png)
since the lines are parallel to each other the slope in both lines are the same
the line formula is
![y-y1=m(x-x1)](https://img.qammunity.org/2023/formulas/mathematics/high-school/w8833wq43gzv073odoa76ku9bunhdf4cj7.png)
since the line passes through the point (- 1, - 1) then
x1 = -1
y1 = -1
![y+1=0(x+1)](https://img.qammunity.org/2023/formulas/mathematics/college/wi45r9ub65fv824bzwdecv84e9hv41bqwj.png)
then the equation in slope point form is
![y+1=0(x+1)](https://img.qammunity.org/2023/formulas/mathematics/college/wi45r9ub65fv824bzwdecv84e9hv41bqwj.png)