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Enter an equation in point-slope form for the line. Slope is -6 and (1,7) is on the line. The equation of the line in point slope form is:

User Dribbel
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2 Answers

5 votes

The point slope form of a straight line is given as,


\begin{gathered} y-y_1=m(x-x_1) \\ y-(7)=-6(x-1) \\ y-7=-6x+6 \\ y+6x=7+6 \\ y+6x=13 \end{gathered}

Hence, the equation for the straight line is ,


y+6x=13

User Ivan C
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8.0k points
2 votes

Answer:

y - 7 = -6(x - 1)

Explanation:

Pre-Solving

We are given that a line has a slope (m) of -6, and contains the point (1,7).

We want to write the equation of this line in point-slope form.

Point-slope form is given as
y-y_1=m(x-x_1), where m is the slope and
(x_1,y_1) is a point.

Solving

As we are already given the slope and the point, we can plug these values into the formula.

Starting with the slope, replace m with -6.


y-y_1=-6(x-x_1)

Now, replace 1 for
x_1 and 7 for
y_1.

The equation will be:

y - 7 = -6(x - 1)

User Domnantas
by
8.3k points

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