Question

Enter an equation in point-slope form for the line. Slope is -6 and (1,7) is on the line. The equation of the line in point slope form is:

Answer 1

The point slope form of a straight line is given as,

`\begin{gathered} y-y_1=m(x-x_1) \\ y-(7)=-6(x-1) \\ y-7=-6x+6 \\ y+6x=7+6 \\ y+6x=13 \end{gathered}`

Hence, the equation for the straight line is ,

`y+6x=13`

Answer 2

y - 7 = -6(x - 1)

Explanation:

Pre-Solving

We are given that a line has a slope (m) of -6, and contains the point (1,7).

We want to write the equation of this line in point-slope form.

Point-slope form is given as
`y-y_1=m(x-x_1)`, where m is the slope and
`(x_1,y_1)` is a point.

Solving

As we are already given the slope and the point, we can plug these values into the formula.

Starting with the slope, replace m with -6.

`y-y_1=-6(x-x_1)`

Now, replace 1 for
`x_1` and 7 for
`y_1`.

The equation will be:

y - 7 = -6(x - 1)