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As 20 ft ladder reaches a window 18 ft high. How far is the foot of the ladder from the base of the building? Round your answer to the nearest tenth.

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11We are given a problem that can be exemplified in the following diagram:

Since the ladder, the wall and the floor form a right triangle we can use the Pythagorean theorem:


h^{2^{}}=a^2+b^2

Where


\begin{gathered} h=\text{hypotenuse} \\ a=\text{height} \\ b=x \end{gathered}

In this case, the hypotenuse is the length of the ladder and the height is the height of the window. Replacing the known values:


(20)^2=(18)^2+b^2

Solving the square:


400=325+b^2

Now we solve for "b", first by subtracting 325 to both sides:


400-325=b^2

Solving the operation:


75=b^2

Taking square root to both sides:


\sqrt[]{75}=b

Solving the square root:


8.7=b

Therefore, the foot of the ladder is 8.7 feet from the building.

As 20 ft ladder reaches a window 18 ft high. How far is the foot of the ladder from-example-1
User Yashwanth Gurrapu
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