Question

(4k + 5) (k + 1)=0 please help me to this problem please.

Answer 1

`(4k+5)(k+1)=0`
`(4k)(k)+(4k)(1)+(5)(k)+(5)(1)=0`
`4k^2+4k+5k+5=0`
`4k^2+9k+5=0`

then applying the quadratic formula

`k=\frac{-9\pm\sqrt[]{81-(4)(4)(5)}}{2(4)}=(-9\pm1)/(8)`

then the solutions of the equation will be K=-5/4 and K=-1