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A ball is thrown in the air from the top of a building. Its height, in meters above ground, as a function of time, in seconds, is given by h(t) = −4.9t2 + 24t + 7. How long does it take to reach maximum height?

User Gopherkhan
by
7.8k points

1 Answer

4 votes

Given:

There are given the equation:


h(t)=-4.9t^2+24t+7

Step-by-step explanation:

According to the concept:

For any quadratic function:


f(x)=ax^2+bx+c

With the negative leading coefficient, it gets the maximum at:


x=-(b)/(2a)

So,

Apply the above formula to the given question.

Then,

From the given function:


h(t)=-4.9t^(2)+24t+7

Where,


\begin{gathered} a=-4.9 \\ b=24 \end{gathered}

Then,

Put the all values into the given formula:

So,


\begin{gathered} x=-(b)/(2a) \\ x=-(24)/(-2(4.9)) \\ x=(24)/(9.8) \\ x=2.45 \end{gathered}

Final answer:

Hence, it will take 2.45 seconds to get the maximum height.

User Kalpesh Kashyap
by
8.0k points
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