Answer:
Let the type A coffee be
![=x](https://img.qammunity.org/2023/formulas/mathematics/college/1ye1eo60321kt0irebsbvlxoc6mkb0xjkb.png)
Let the type B coffee be
![=y](https://img.qammunity.org/2023/formulas/mathematics/high-school/eyqg7ht214ag7yrcgx5vsdv0indwor49dl.png)
Three times as many pounds of type B coffee as type A, will be represented below as
![y=3x](https://img.qammunity.org/2023/formulas/mathematics/high-school/x3q8kt3l366jfmm89tfr8zil9wuf8fwkg6.png)
The cost of type A coffee is
![=\text{ \$4.10 per pound}](https://img.qammunity.org/2023/formulas/mathematics/high-school/c260h0kvthp6abnay155jnymihnda8vm3w.png)
The cost of type B is
![=\text{ \$5.25 per pound}](https://img.qammunity.org/2023/formulas/mathematics/high-school/6n82i7ighsuayf0m1tavu86cnk7m4eje3v.png)
The total cost of both coffee is
![=\text{ \$635.20}](https://img.qammunity.org/2023/formulas/mathematics/high-school/r04jqg7bsf86mq4nyygnu99kkypo2cu7m9.png)
Hence,
The equation will be
![\begin{gathered} 4.10x+5.25y=635.20 \\ 4.10x+5.25(3x)=635.20 \\ 4.10x+15.75x=635.20 \\ 19.85x=635.20 \\ (19.85x)/(19.85)=(635.20)/(19.85) \\ x=32 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/x7jdt51j6sb4szay56fljkfgzhavtjbcpp.png)
Hence,
The number of pounds of type A coffee is = 32 pounds