Recall that:
1) The solution set of the inequality:

is the following interval:

2) The solution set of the inequality:
.](https://img.qammunity.org/2023/formulas/mathematics/college/mra3z234wd7w2rylgfbqjgy57kf0lac6oa.png)
Therefore the solution set of the given inequalities is:

Since -5<-2 then:

Therefore:

The representation of the above interval in a number line is:
Answer: