Question

if an object travelling at 198 km/hr accelerates at 2.00 m/s ^2 for 3.40 seconds, how far has the object traveled?

Answer 1

We know that

• The initial velocity is 198 km/hr.

,

• The acceleration is 2m/s^2.

,

• The time elapsed is 3.40 seconds.

We have to find the distance covered. To do that, use the following formula that relates to initial velocity, time, acceleration, and distance.

`\begin{gathered} d=v_0t+(1)/(2)at^2 \\ \end{gathered}`

But, first, we have to transform 198 km/hr to m/s. We know that 1 km equals 1000 m, and 1 hr equals 3600 seconds.

Once we transform the speed, we are able to find the distance traveled.

`\begin{gathered} d=55((m)/(s))\cdot3.4\sec +(1)/(2)\cdot2((m)/(s^2))\cdot(3.4\cdot(m)/(s))^2 \\ d=187m+11.56m \\ d=198.56m \end{gathered}`

Therefore, the object traveled 198.56 meters.