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A study of wait times at Texas roadhouse a random sample of 63 patrons were asked how long their wait times was. The study concluded that their wait times were normally distributed with a mean wait time of 28.4 minutes and a standard deviation of 3.6 minutes. what range of values represents the middle 95% of the data?

User Estradiaz
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1 Answer

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Let's use Probability mass function:


P(X)=\frac{1}{\sigma\sqrt[]{2\pi}}e^{-((x-\mu)^2)/(2\sigma^(^2))}

Where:


\begin{gathered} \sigma=\text{ Standard deviation = 3.6} \\ \mu=\operatorname{mean}=28.4 \end{gathered}


P(X)=(0,22.3)

User Lasonya
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