Question

Hello, I need quick help with this math question please

Answer 1

Given:

`3(x-9)^2=21`

Simplify:

`3x^2-54x+222=0`

Use the quadratic formula to solve for the values of x.

a = 3

b = -54

c = 222

`x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}`
`x=\frac{-(-54)\pm\sqrt[]{(-54)^2-4(3)(222)}}{2(3)}`
`x=\frac{54\pm\sqrt[]{2916-2664}}{6}`
`x=\frac{54\pm\sqrt[]{252}}{6}`

Solve for x (1)

`x=\frac{54+\sqrt[]{252}}{6}`
`x=(54)/(6)+\frac{6\sqrt[]{7}}{6}`
`x=9+\sqrt[]{7}`

Solve for x (2)

`x=\frac{54-\sqrt[]{252}}{6}`
`x=(54)/(6)-\frac{6\sqrt[]{7}}{6}`
`x=9-\sqrt[]{7}`

Therefore, the answer would be C.

`x=9\pm\sqrt[]{7}`