Answer:

Explanations:
From the given question, we are given the weight of two bags to be 10 2/3kg and 6 1/2kg.
The total weight of the bags will be equal to the sum of the individual weight as shown:

Convert to improper fraction to have:

Find the Lowest Common Multiple and take the sum

Convert the result into a mixed fraction to have:

Hence the total weight of the bag is 17 1/6kg