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If ZR and ZT are supplementary angles, mZR = (6X - 4)', and mZT= (2x + 16), find mZT?

If ZR and ZT are supplementary angles, mZR = (6X - 4)', and mZT= (2x + 16), find mZT-example-1
User Lemon Drop
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1 Answer

4 votes

First we will draw the angles for better understanding

To find JML we will use the supplementary angles


\begin{gathered} \text{JML}=KJ-\text{LMK} \\ \text{JML}=180º-154º \\ \text{JML}=26º \end{gathered}

To find NMK we will use the supplementary angles again becase LN=180º


\begin{gathered} LN=180º \\ \text{NMK}=LN-\text{LMK} \\ \text{NMK}=180º-154º \\ \text{NMK}=26º \end{gathered}

finally we use the complementary angles to find PMN


\begin{gathered} \text{PMN}=90º-\text{NMK} \\ \text{PMN}=64º \end{gathered}

If ZR and ZT are supplementary angles, mZR = (6X - 4)', and mZT= (2x + 16), find mZT-example-1
User Googie
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