Solution:
When a function f(x) is stretched vertically by a factor of an integer n, it implies that the new function g(x) is n times its old function.
Thus,

Given a square root function, we have
![f(x)=\sqrt[]{x}](https://img.qammunity.org/2023/formulas/mathematics/college/eoshqhavec9ovuzgludbh20udpt0k7hgf6.png)
When the function is stretched by a factor of 6, let the new function be represented as G(x). This implies that
![\begin{gathered} G(x)=6* f(x) \\ =6*\sqrt[]{x} \\ \Rightarrow G(x)=6\sqrt[]{x} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ddnmrdahfdigikrxfsqoa2w3276quipzph.png)
Hence, the new function G(x) will be expressed as
![G(x)=6\sqrt[]{x}](https://img.qammunity.org/2023/formulas/mathematics/college/rh5me3a1352i96z49733hqkb8jki1e18dk.png)
The correct option is A.