Question

Expand the square of a binomial (8ab-8)^2

Answer 1

`\begin{gathered} 1.When\text{ you have this }(a-b)^2\text{ you can expand it like this }a^2-2ab+b^2 \\ 2.In\text{ this case }you\text{ have }(8ab-8)^2 \\ 3.\text{ In the first step you can se}e\text{ } \\ a=8ab \\ b=-8 \\ 4.\text{ Here you re}place\text{ the values }(8ab-8)^2=(8ab)^2-2\cdot(8ab)\cdot(8)+(-8)^2 \\ \mleft(8ab-8\mright)^2=64a^2b^2-128ab+64 \\ \text{The expand of the binomial }(8ab-8)^2\text{ is }64a^2b^2-128ab+64 \end{gathered}`