Question

B) Given: y = 2x - 1 (x-3) (x+1) what is the I. VAII. HAIII. X-intercept IV. Y-Intercept

Answer 1

Case: Equations

Method:

`\begin{gathered} y=2x-1(x-3)(x+1) \\ y=2x-[x^2+x-3x-3] \\ y=2x-[x^2-2x-3] \\ y=2x-x^2+2x+3 \\ y=3-x^2+2x+2x \\ y=3+4x-x^2 \end{gathered}`

The following:

1. Vertical asymptote: None

2. Horizontal asymptote: None

3. x-intercept

`\begin{gathered} y=3+4x-x^2 \\ 0=3+4x-x^2 \\ x^2-4x-3=0 \\ x=(-(-4)\pm√((-4)^2-4(1)(-3)))/(2(1)) \\ x=-0.646\text{ }or\text{ }4.646 \end{gathered}`

4. y-intercepts

`\begin{gathered} y=3+4x-x^2 \\ y=3+4(0)-(0)^2 \\ y=3 \end{gathered}`

Final answer:

I) None

II) None

III) (-0.646, 0), (4.646, 0)

IV) (0, 3)