1 Answer

JackW · Answer 1 · 2023-01-11T03:07:13+0000

We have this first condition given:

$x+y=\text{ 10 (1)}$

And the second one:

$x-2y=\text{ 8 (2)}$

If we solve for x from equation (1) we got:

$x=\text{ 10}-y\text{ (3)}$

And if we solve for x from equation (2) we got:

$x=\text{ 8+2y (4)}$

Now we can set equal equations (3) and (4)

$10-y=\text{ 8+2y}$

And solving for y we got:

$18=\text{ 3y }\rightarrow\text{ y= }(18)/(3)=\text{ 6}$

Final answer:

$y=\text{ 3}\cdot6\text{ = 18}$

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