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Tickets for a dance recital cost $24 for adults and $6 dollars for children. The dance company sold 229 tickets and the total receipts were $3,264. How many adult tickets and how many child tickets were sold?

User Tchaymore
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1 Answer

7 votes

Let:

a be the number of adults.

c be the number of children.

To solve this question, follow the steps below.

Step 01: Write an equation for the total of tickets sold.

Since the company sold 229 tickets for adults and children:


a+c=229

Step 02: Write an equation for the total receipts.

The total receipt of $3,264 is the sum of the receipts from the adults' tickets and the children's ticket.

Then,


24a+6c=3,264

Step 03: Isolate a in the first equation and substitute it in the second equation.


a+c=229

To isolate a, subtract c from both sides.


\begin{gathered} a+c-c=229-c \\ a=229-c \end{gathered}

Substituting a in the second equation:


24\cdot(229-c)+6c=3,264

And solving the equation for c:


\begin{gathered} 24\cdot229-24\cdot c+6c=3,264 \\ 5,496-18c=3,264 \\ \end{gathered}

Subtracting 5,496 from both sides:


\begin{gathered} 5,496-18c-5,496=3,264-5,496 \\ -18c=-2,232 \end{gathered}

And dividing both sides by -18:


\begin{gathered} (-18)/(-18)c=(-2,232)/(-18) \\ c=124 \end{gathered}

Step 04: Use the value of c to find a.


\begin{gathered} a=229-124 \\ a=105 \end{gathered}

Answer:

Adult tickets sold: 109.

Chil tickets sold: 124.

User Carloluis
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