Question

Find the distance CD rounded tothe nearest tenth.C = (6,-5) and D = (-1,-4)CD = [? ]HINT: Use the distance formula:d = v(x2 - xı)2 + (72 - yı)2

Answer 1

To determine the distance between the two points we need to use the following expression:

`d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}`

Where (x1,y1) and (x2,y2) are the coordinates for the two points. The ones that were given to us were: (6,-5) and (-1,-4).

`\begin{gathered} d=\sqrt[]{(6-(-1))^2+(-5-(-4))^2} \\ d=\sqrt[]{(6+1)^2+(-5+4)^2} \\ d=\sqrt[]{7^2+(-1)^2} \\ d=\sqrt[]{49+1}=\sqrt[]{50}=7.07 \end{gathered}`

The distance between the points is approximately 7.1