Question

Find the value of x in the givenright triangle.12x = [?]62°хEnter your answer as a decimal rounded to thenearest tenth.

Answer 1

Given:

Angle =62 degrees.

Adjacent side=x and Hypotenuse=12.

Consider the cosine formula

`\cos \theta=\frac{Adjacent\text{ side}}{\text{Hypotenuse}}`

Substitute Angle =62 degrees, Adjacent side=xm and Hypotenuse=12, we get

`\cos 62^o=(x)/(12)`

`12*\cos 62^o=x`

`12*0.4695=x`
`x=5.6`

Hence the value of x is 5.6 units.