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4(x+2)^2-5=11solve for x

1 Answer

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You have the following equation:

4(x+2)² - 5 = 11

in order to solve the previous equation, proceed as follow:

4(x+2)² - 5 = 11 expand the squared factor

4(x² + 4x + 4) - 5 = 11 apply distribution property

4x² + 16x + 16 - 5 = 11 simplify like terms left side

4x² + 16x + 11 = 11 subtract 11 left side

4x² + 16x = 0 divide by 4 both side

x² + 4x = 0 factorize x both sides

x(x + 4) = 0

from the previous equation, you obtain that x is:

x = 0

x+ 4 = 0 => x = -4

Hence, the solutions for x are 0 and -4

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