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An object starts from rest and moves a distance d due to the presence of a net force F_net . If the net force is doubled ( F'_net = 2F_net ) while keeping the same distance d , then which of the statements below cannot be true ?

An object starts from rest and moves a distance d due to the presence of a net force-example-1

1 Answer

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Given data:

The net force in case I is F_net.

The net force in case II is F'_net=2F_net.

The distance traveled is d.

The work energy theorem is given by,


KE=W

Here, KE is the kinetic energy, and W is the work done.

The work done in case I is,


W=F_(net)d

The work done in case II is,


\begin{gathered} W^(\prime)=F^(\prime)_(net)d \\ W^(\prime)=2F_(net)d \end{gathered}

The ratio of kinetic energy will be,


\begin{gathered} (KE)/(KE^(\prime))=(W)/(W^(\prime)) \\ (KE)/(KE^(\prime))=(F_(net)d)/(2F_(net)d) \\ KE^(\prime)=2KE \end{gathered}

Thus, the final kinetic energy is doubled.

Final Answer:

Its final kinetic energy is doubled.

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