Question

What work was done by the dartboard and stopping the dark into what form does the dart Connecticut energy change

Answer 1

Given data:

* The mass of the dart is m = 0.025 kg.

* The speed of the dart is v = 13 m/s.

Solution:

(a). The work done by the dartboard to stop the dart is,

`W=(1)/(2)mv^2`

Substituting the known values,

`\begin{gathered} W=(1)/(2)*0.025*13^2 \\ W=2.1125\text{ J} \end{gathered}`

Thus, the amount of work done by the dartboard is 2.1125 J.

(b). As the friction of dartboard