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Suppose the population of a town is 9800 and is growing 2% each year reign equation models the population growth predict the population after seven years

Suppose the population of a town is 9800 and is growing 2% each year reign equation-example-1
User Panic
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1 Answer

3 votes

Answer:


y=9,800*1.02^x;about\text{ 11,257 people}

Step-by-step explanation:

Given:

Initial population(a) = 9800

Rate of increase in decimal(r) = 2% = 2/100 = 0.02

Time period(x) = ?

To find:

Equation model and population after 7 years

Recall the below exponential growth function;


y=a*(1+r)^x

Let's go ahead and substitute the given value into the above to have the equation that models the population growth;


\begin{gathered} y=9800*(1+0.02)^x \\ y=9800*1.02^^x \end{gathered}

When x = 7, let's go ahead and solve for y;


\begin{gathered} y=9800*1.02^7 \\ y=9800*1.14868566765 \\ y=11,257 \end{gathered}

So the population after 7 years will be 11,257 people

User Geoffrey
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