Question

17. In the diagram below, DE, DF, and EF are midsegments of AABC. K b P с The perimeter of quadrilateral ADEF is equlvalent to A. AB + BC + AC AB + = AC C. 2AB + 2AC D. AB + AC

Answer 1

we are asked to determine the perimeter of quadrilateral ADEF. The perimeter is the sum of the sides of a figure, therefore, the perimeter "P" is:

`P=AD+DE+EF+FA`

Now, we have that DE = FA and AD = EF, therefore:

`P=2AD+2DE`

Since triangle DEF is midsegments of triangle ABC we have 2AD = AB and 2DE = AC, therefore:

`P=AB+AC`