Question

What is the y-intercept of the function y=-1/2 cos (3x/2)

Answer 1

we have the following:

`\begin{gathered} y=-(1)/(2)\cos ((3)/(2)x) \\ x=0 \\ y=-(1)/(2)\cos ((3)/(2)\cdot0) \\ y=-(1)/(2)\cos (0)=-(1)/(2)\cdot1 \\ y=-(1)/(2) \\ (0,-(1)/(2)) \end{gathered}`

therefore, the y-intercept is (0, -1/2)