We know that
• The average is 7 pounds.
,
• The standard deviation is 1.23 pounds.
To label 3 standard deviations on the right, we have to add them to the mean. To label 3 standard deviations on the left, we have to subtract from the mean.
Right.

Left.

Let's sketch the graph
Let's find Jessica's and Maria's z-score.

Maria's daughter's weight could be considered an outlier because it's far away from the mean of 7 pounds.
So, we should be concerned about Maria's daughter because her way is too high.