Question

A dog escapes his backyard and he walks 15 m south and then 7 m east before stopping what was his displacement?

Answer 1

Given:

Distance walked = 15 m south

Then the dg now walked 7 m east before stopping.

Let's find the displacement.

The figure below represents this situation:

The displacement can be said to be the shortest distance from the final position to the ending position.

To find the displacement here, apply Pythagorean theorem:

`d=\sqrt[]{a^2+b^2}`

Where:

a = 15 m

b = 7 m

Thus, we have:

`\begin{gathered} d=\sqrt[]{15^2+7^2} \\ \\ d=\sqrt[]{225+49} \\ \\ d=\sqrt[]{274} \\ \\ d=16.55\text{ m} \end{gathered}`

Therefore, the displacement is 16.55 m.

ANSWER:

16.55 m