Given:
We get two points from the table of car A are (15,1) and (75,5).
We get two points from the table of car B are (45,1) and (180,4).
Required:
We need to determine which car is traveling at the greatest speed and by how much.
Step-by-step explanation:
Consider the formula to find the speed of the car.
![Speed=(distance)/(time)](https://img.qammunity.org/2023/formulas/mathematics/high-school/aon9z0zsgtd70anpjiafxuztr82yh3czdj.png)
Consider the point (15,1).
Substitute distance =15 and time =1 in the formula to find the speed of car A.
![Speed\text{ of car A}=(15)/(1)](https://img.qammunity.org/2023/formulas/mathematics/college/ad4cqhbtfnxz0hv4n7i0bxijzes1k22yys.png)
![Speed\text{ of car A}=15miles\text{ per hour}](https://img.qammunity.org/2023/formulas/mathematics/college/s46tjmvq9vj08y4gajjpnjy8rqzzf5o5mt.png)
Consider the point (45,1).
Substitute distance =45 and time =1 in the formula to find the speed of car B.
![Speed\text{ of car B}=(45)/(1)](https://img.qammunity.org/2023/formulas/mathematics/college/yywtwlluitgy0bfx0oxmgp76p2gni4z9qk.png)
![Speed\text{ of car B}=45miles\text{ per hour}](https://img.qammunity.org/2023/formulas/mathematics/college/i7hb2j8kjrc1ytewe6a8de1rnh8yzy0it7.png)
![\text{We know that }45>15.](https://img.qammunity.org/2023/formulas/mathematics/college/qyqzlm4789gjcoc6g1rw4gdraf8hy1iv1j.png)
The speed of car B is the greatest speed.
Subtract 45 from 15, we get
![45-15=30\text{ miles per hour.}](https://img.qammunity.org/2023/formulas/mathematics/college/ujjyo7ga40wjgb4fui35srwrv8mhp3t7o3.png)
The speed of car B is 30 miles per hour greater than car A.
Final answer:
The speed of car B is the greatest speed.
The speed of car B is 30 miles per hour greater than car A.