we have
x^3 + 6x = 5x^2
x^3-5x^2+6x=0
Factor x
x(x^2-5x+6)=0
x^2-5x+6=(x-2)(x-3)
substitute
x^3-5x^2+6x=x(x-2)(x-3)
the solutions are
x=0
x=2
x=3
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