Question

A circle has a center at (-4,-5) and a radius of √6. What is the equation of the circle

Answer 1

Given:

The center of the circle is, (h, k) = (-4, -5)

The radius of the circle is, r =√2.

The general equation for a circle is given by,

`(x-h)^2+(y-k)^2=r^2`

Substituting the values, we have,

`\begin{gathered} (x-(-4))^2+(y-(-5))^2=(\sqrt[]{6})^2 \\ (x+4)^2+(y+5)^2=6 \end{gathered}`