Given:
The total number of students, N=160.
The number of students taking sequence course, n(S)=76.
The number of students taking analysis course, n(A)=85.
The number of students taking sequence and analysis courses , n(S∩A)=33.
The number of students taking analysis and probability courses, n(A∩P)=35.
The number of students taking sequence, analysis and probability courses, n(S∩A∩P)=15.
The number of students taking only sequence course, n(s)=32.
Since each student takes atleast one math course, the total number of students is,
The venn diagram formula can be written as,
We use Venn diagram to solve the question. Let S represenst students taking sequence course, A represenst students taking analysis course and P represenst students taking probability course.
The students taking only analysis and sequence courses is,
The students taking only analysis and probability courses is,
(b)
The students taking only sequence and probability lessons without analysis is,
Hence, the number of students taking only sequence and probability lessons without analysis is 11.
(a)
Using the Venn diagram, the number of students taking only probability course is,
n(p)=160-32-18-11-15-32-20=32
Now, the number of students taking a probability course is,
n(P)=11+15+20+32=78.
Therefore, the number of students taking a probability course is 78.
(c)
The students that take only one course from the venn diagram is
N=32+32+32=96
Therefore, the students that take only one course is 96.