Question

I need help with answering this practice problem. It’s pre calculus

Answer 1

Based on the given summation, you can notice that it can be written as follow:

`\sum ^6_(i\mathop=1)6i+5`

In fact, if you replace the values of i into the summation, you obtain:

`\begin{gathered} \sum ^6_{i\mathop{=}1}6i+5=(6+5)+(12+5)+(18+5)+(24+5)+(30+5)+(36+5) \\ \sum ^6_{i\mathop{=}1}6i+5=11+17+23+29+35+41 \end{gathered}`