Question

What is the equation in slope-intercept form of the line that passes through the point (2,-2) 2 and is perpendicular to the line represented by y = x + 2? A Y EX- су- DY---

Answer 1

`\begin{gathered} \text{POINT (2,-2)} \\ Perpendicula\text{ to the line y=}(2)/(5)x+2 \\ \text{FIND SLOPE-INTERCEPT EQUATION} \\ \text{Two lines are perpendicular when slope1}\cdot slope2=\text{ -1} \\ \text{slope1}\cdot slope2=\text{ -1} \\ ((2)/(5))\cdot slope\text{ 2=-1} \\ \text{slope 2=-1 }\cdot((5)/(2)) \\ \text{slope 2 =-}(5)/(2) \\ y=\text{-}(5)/(2)x+b \\ U\sin g\text{ the point (2,-2)} \\ -2=\text{-}(5)/(2)\cdot(2)+b \\ -2=-5+b \\ b=-2+5 \\ b=3 \\ y=\text{-}(5)/(2)x+3 \\ \\ \text{The slope-intercept is }y=\text{-}(5)/(2)x+3 \end{gathered}`