Let A be the event that exactly one of the sampled tiles is defective.
In a batch of 17 tiles, 7 are defectives.
3 tiles are sampled at random.
3 tiles can b eselected from 17 tiles in
![^(17)C_3=680](https://img.qammunity.org/2023/formulas/mathematics/college/k7rj4gfphna376oqywfsjfzqhja53z67fx.png)
ways.
Therefore, the number of points in sample space is 680.
Now, 1 defective item can be selected from 7 defetctive items in 7 different ways. For each of these ways, remaining two items can be selected from (17-7)=10 non-defective items in
![^(10)C_2=45](https://img.qammunity.org/2023/formulas/mathematics/college/rigwrqdoosl04jdurush1kgwzgciwnqopl.png)
ways.
Therefore, from the batch of 17 tiles, 3 items can be selected so that exactly one item is defective in
![45*7=315](https://img.qammunity.org/2023/formulas/mathematics/college/pvpf012yeg32a67v46eo26wer08t9uzwvu.png)
ways.
Therefore, total number of points in sample space in favour of the event A is 315.
By classical definition of probability,
![\begin{gathered} P(A)=(315)/(680) \\ =(63)/(136) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/9i2uspnpz6k01giavj394b7cz5j0augkdp.png)
Hence, the probability that exactly 1 of the sampled tiles is defective is
![(63)/(136)\approx0.46](https://img.qammunity.org/2023/formulas/mathematics/college/8dbnw3zpwjmxfp8jq6i6j1ulxdlbvtjp25.png)