Question

Based on the answer from question #1 , if she graphed the function correctly, explain how you know that. If she graphed the function incorrectly, explain what she did wrong and what the correct graph should look like HELP ME

Answer 1

Check Explanation

Step-by-step explanation

We are told to check whether the graph plotted is for the function

3y = -12 + 3x

The best way to investigate this is to insert x = 0, get the value of y

Then, insert y = 0, solve for x

3y = -12 + 3x

when x = 0,

3y = -12 + 3(0)

3y = -12

Divide both sides by 3

(3y/3) = (-12/3)

y = -4

This indicates that when x = 0, y = -4. This shows that this graph isn't the graph of this function because on the graph, when x = 0, y = -12.

when y = 0,

3y = -12 + 3x

3(0) = -12 + 3x

0 = -12 + 3x

3x = 12

Divide both sides by 3

(3x/3) = (12/3)

x = 4

(4, 0)

The correct graph would have the line pass through (0, -4) and (4, 0).

Hope this Helps!!!