27.8k views
1 vote
determine whether each ordered pair is a solution to the inequality (2, 10), (-5, -4), (-5, -8), (0, 4) (-8, -2)

determine whether each ordered pair is a solution to the inequality (2, 10), (-5, -4), (-5, -8), (0, 4) (-8, -2)-example-1
User Shriram V
by
8.1k points

1 Answer

0 votes
Solution of an inequality

In order to find if an ordered pair is a solution of

x + y > 3

we just need to add x + y using x and y values of the given ordered pairs. Then, we analyze if x + y is bigger or lower than 3

Remember that an ordered pair is given by (x, y). Then we just add the given numbers

(2, 10)

x + y = 2 + 10 = 12

(-5, -4)

x + y = - 5 - 4 = -9

(-5, -8)

x + y = -5 - 8 = -13

(0, 4)

x + y = 0 + 4 = 4

(-8, -2)

x + y = - 8 - 2 = - 10

The correct ordered pairs will be those whose result is > 3 (this mean the numbers bigger than 3). We just have two (0, 4) result is 4 and (2, 10) was 12, then

Answer: the ordered pairs that are solutions of x + y > 3 are

(0, 4) and (2, 10)

User Wheleph
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories