You have the following expression:
![(1)/(4)(3\cdot7)](https://img.qammunity.org/2023/formulas/mathematics/college/cj3q642d41hn9ydt6l697shq0bb2ypc7c8.png)
You need to evaluate. First multiply the numbers inside the parentheses and then multiply the result with the fraction.
Then, you get this product:
![(1)/(4)(3\cdot7)=(1)/(4)(21)=(21)/(4)](https://img.qammunity.org/2023/formulas/mathematics/college/9uwkgct958wq29e88v80bj8ukf7lihyrvz.png)
Now divide the numerator by the denominator to get the number in decimal form:
![=5.25](https://img.qammunity.org/2023/formulas/mathematics/high-school/48mvh28xowcdwg8qtn889k0uycbuqvzytb.png)
Evaluate the second expression by solving the multiplication. You get that its product is:
![(3\cdot7)=21](https://img.qammunity.org/2023/formulas/mathematics/college/zpaecvo8f1aasi37tlpkff95ivlr2qef2d.png)
As you can notice, 21 is greater than 5.25 , therefore:
![\begin{gathered} (3\cdot7)>(1)/(4)(3\cdot7) \\ 21>5.25 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/1ywlttecpc1r6ducm39p73lp8x16tvgfui.png)