Given:
A hiker travels 12 km in a direction of 50 degrees west of north.
To find:
The north and west components of displacement.
Step-by-step explanation:
From the diagram,
The distance traveled by the hiker in a direction of 50 degrees west of north is:
OP = 12 km
The north component of displacement is given as:
![N=OPcos\theta=12\text{ km}* cos50\degree=7.71\text{ km}](https://img.qammunity.org/2023/formulas/physics/college/yuke42sr8a7r5z1b8cstf3cj8mmahz9iuy.png)
The west component of displacement is given as:
![W=OPsin\theta=12\text{ km}* sin50\degree=9.19\text{ km}\approx9.2\text{ km}](https://img.qammunity.org/2023/formulas/physics/college/h7w3ib4uhtxizy33ixh26yan60lruof09c.png)
Final answer:
The north component of displacement is 7.71 km and the west component of displacement is 9.2 km.