Question

I need help please ..

Answer 1

Answer: y = -3x + 1

Slope-point form:

`y+5=-3(x-2)`

Let us simplify the equation to form the slope-intercept form of the equation of the line.

`\begin{gathered} y+5=-3(x-2) \\ y+5=-3x+6 \\ y=-3x+6-5 \\ y=-3x+1 \end{gathered}`

Therefore, its slope-intercept form is y = -3x + 1.