The root method requires us to leave the expression that is raised to the power of 2 on one side of the equality. We do so, by applying mathematical operations on both sides of the equation
We begin with the equation
![2(x-4)^(2)-6=18](https://img.qammunity.org/2023/formulas/mathematics/college/icuyezbu1s7toia7nzr4wtj6ui70j3i7j9.png)
First, we add 6 on both sides, so we get
![2(x-4)^(2)=18+6=24](https://img.qammunity.org/2023/formulas/mathematics/college/lxn7uufuxykhbw12lqcp39o89h91917s6l.png)
Then, we divide boths sides by 2, so we get
![(x-4)^(2)=(24)/(2)=12](https://img.qammunity.org/2023/formulas/mathematics/college/i5sra3n5rbso3n108spv5gmvotioe8h5m5.png)
Now, we take the square root on both sides. Have in mind that once we take the square root we should consider the positive and negative root. So we get
![x-4=\pm\sqrt[]{12}](https://img.qammunity.org/2023/formulas/mathematics/college/bc4zjthu4zjwfn6ufdbji0yl6tawpqzltp.png)
Finally, we add 4 on both sides, so we get
![x=4\pm\sqrt[]{12}](https://img.qammunity.org/2023/formulas/mathematics/college/nsxzagesrzwaepnx89dypxj1fzimioiaiq.png)
This is equivalent to have the solutions
![x=4+\sqrt[]{12}](https://img.qammunity.org/2023/formulas/mathematics/college/dquhz568kmr761s311unwp29f843iahojp.png)
and
![x=4-\sqrt[]{12}](https://img.qammunity.org/2023/formulas/mathematics/college/2vwhqyajg94vs3nwry60x5fvi641gbpuod.png)