Question

A silver wire is 5.6 m long and 0.80 mm in diameter. What is its resistance?

Answer 1

Given

The length is l=5.6 m

The diameter is d=0.80 mm

To find

The resistance of the silver.

Step-by-step explanation

We know the resistivity of silver is

`\rho=1.59*10^(-8)\Omega.m`

The resistance is given by

`\begin{gathered} R=(\rho l)/(\pi((d)/(2))^2) \\ \Rightarrow R=(1.59*10^(-8)*5.6)/(\pi((0.8*10^(-3))/(2))^2) \\ \Rightarrow R=0.177\Omega \end{gathered}`

Conclusion

The resistance is

`0.177\Omega`