Question

What is the slope of a line that is perpendicular to the line shown?(0, 3)(3, 2)

Answer 1

Answer: The slope of the line perpendicular to a provided slope is in general as follows:

`m_p=-(1)/(m)`

Therefore for the particular provided case, it is as follows:

`\begin{gathered} m=(\Delta y)/(\Delta x)=(3-2)/(0-3)=-(1)/(3) \\ \\ m=-(1)/(3) \\ \\ \therefore\rightarrow \\ \\ m_p=-(1)/(m)=-(1)/((-(1)/(3)))=3 \\ \\ m_p=3 \end{gathered}`

Therefore the new slope is 3.