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Discriminant for x^2-4x+1=-3

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The given equation is


x^2-4x+1=-3

First, we have to move the term -3


\begin{gathered} x^2-4x+1+3=0 \\ x^2-4x+4=0 \end{gathered}

Where a = 1, b = -4, and c = 4.

The discriminant formula is


D=b^2-4ac

Replacing the values, we have


D=(-4)^2-4(1)(4)=16-16=0The discriminant is zero.

Given that the discriminant is zero, it means the equation has a unique solution.

User JRulle
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