Question

Hello I need help with this question. I started it but am confused

Answer 1

Given:

The mass on the table is,

`m=1.0\text{ kg}`

The hanging mass is,

`M=1.5\text{ kg}`

THe coefficient of friction is,

`\mu=0.20`

let the acceleration of the whole system is a (for the hanging mass it is downward and for the mass on the table it is rightward). the tension towards The fixed point of the pulley is T.

we can write,

`Mg-T=Ma\ldots.\ldots..\ldots\ldots.(1)`
`ma=T-\mu mg\ldots.\ldots.\ldots..\ldots..(2)`

Adding these equations we get,

`\begin{gathered} (M+\mu m)g=(M+m)a \\ a=((M+\mu m)g)/(M+m) \end{gathered}`

Substituting the values we get,

`\begin{gathered} a=((1.5+0.20*1.0)9.8)/(1.5+1.0) \\ =6.67m/s^2 \end{gathered}`

Hence the acceleration is 6.66 m/s^2.