In order to determine the values of x and y, proceed as follow:
- Consider that the bigger and smaller triangle are similar, then, they have similar sides in which thier proportion are equal. Based on the given image you can write:

By solving for y, you get:
![\begin{gathered} y^2=28*8 \\ y=\sqrt[\placeholder{⬚}]{224} \\ y=4\sqrt[\placeholder{⬚}]{14} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/vv4xkc4jftetyy213stkbef8we4snsamz0.png)
- Now, use the Pythagorean theorem to find the value of x:
![\begin{gathered} 28^2=x^2+y^2 \\ x^2=28^2-y^2 \\ x=\sqrt[\placeholder{⬚}]{28^2-(4\sqrt[\placeholder{⬚}]{14})^2} \\ x=4\sqrt[\placeholder{⬚}]{35} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/237kjrwqnus7ipc1gfb54tymsp20bzw5ki.png)
Hence, the values of x and y are:
x = 4√35
y = 4√14
Fourth option