Question

Pleas I need help with this math problem it can’t be a fraction

Answer 1

Given the expression;

`(n^(-7)p^7)^(-8)`

First, we expand the expression using the indices rule that;

`(ab)^c=a^cb^c`

So, the expression is;

`(n^(-7)p^7)^(-8)=(n^(-7))^(-8)*(p^7)^(-8)`

So, we apply another rule;

`(a^b)=a^(b* c)=a^(bc)`

Thus, we have;

`\begin{gathered} (n^(-7))^(-8)*(p^7)^(-8)=n^(56)* p^(-56) \\ (n^(-7)p^7)^(-8)=n^(56)p^(-56) \end{gathered}`

Then, we have;

`\begin{gathered} n^(56)p^(-56)=(n^(56))/(p^(56)) \\ n^(56)p^(-56)=((n)/(p))^(56) \end{gathered}`